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Q.

A juggler throws next ball when previous ball is at maximum height. if he throws two balls per second then the maximum height attained by each ball is(g=10m/s) (A)5m (B)12.5m (C)1.25m (D)0.125m

Updated 7 months ago

Solution

As the juggler throws two $balls/s$, time taken to reach maximum $height = 1 s$ Here, time of ascent = time of descent Use $S= ut + \frac 12 gt^2$ ( for downward motion ) $u = 0$ $S =\frac 12 gt^2$ $= \frac 12 (10) (1)^2$ $= 5 m$ Hence, option (a) is the correct answer

Updated 7 months ago

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