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Please solve Q9

If 3 \( sin^2A + 2sin^2B = 1 \) and 3 \(sin2A - 2\) \(sin2B = 0\), where A and B are acute angles, then \(A + 2B\) is equal to

(a) \(\frac {\pi}{3}\)

(b) \(\frac {\pi}{4}\)

(c) \(\frac {\pi}{2}\)

(d) none of these

Updated Thu, 30 May 2019 02:57 pm

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