• JEE Main & Advanced
• 
• 11th
• 
• Physics
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Q.

The relation between time \(t\) and distance \(x\) is \(t = \alpha x^2 + \beta x\), where \(\alpha\) and \(\beta\) are constants. The retardation is (v is the velocity)

(a) \(2 \alpha v^3\)

(b) \(2 \beta v^3\)

(c) \(2 \alpha \beta v^3\)

(d) \(2 \beta^2 v^3\)