Flat 50% off
BUY NOWEnds in
what s velocity sir...
Updated Wed, 19 Jun 2019 10:39 am
WE KNOW THAT R=mv/qb..... how can we get \(R=\frac{1}{B} \sqrt{\left(\frac{2 m V}{q}\right)}\) ...... v is velocity of charge particle and.... V is voltage of current
Updated Tue, 18 Jun 2019 04:52 pm