Flat 50% off
BUY NOWEnds in
A particle is projected from a pipe at an angle \(\theta = 45^o\) wtih the vertical at a point P with a speed \(u = 10 ms^{-1}\). A strong horizontal wind gives a constant horizontal acceleration equal to \(5 ms^{-2}\) to the particle such that the particle reaches the ground at point Q which is exactly below P. The height of point P (in m) from the ground is \([g = 10 ms^{-2}]\)
(a) 30
(b) 40
(c) 50
(d) 60
Updated Thu, 20 Sep 2018 04:33 pm
Can you please explain what excision of bacterial dna means?
Updated Tue, 18 Sep 2018 12:05 pm