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The given aldoxime should be a anti-aldoxime. Isn't it? (Since in case of aldoximes, the priority is given to the LP rather than the -OH group. Inversely the priority is given to -OH group rather than the LP, in case the given compound is ketoxime) If not so, is there any other specific reason ?
Updated Wed, 21 Nov 2018 03:13 pm


In what way the reaction will occur in case of addition of alkenes, in the presence of H2SO4, specifically at 80 degree Celsius temperature ? Is it the same as shown in the video no. 8 of chapter Hydrocarbons ? (We have got a product with 7 carbons, whereas we have only 6 carbons on the left side of the reaction.) If not, then what will be the actual product in that case ?
Updated Wed, 21 Nov 2018 03:11 pm