Flat 50% off
BUY NOWEnds in


\(T_1 = \frac{Mg}{sin\alpha \frac{cos \alpha}{cos \beta}sin \beta}\)
\(= \frac{Mg cos \beta}{sin(\alpha+\beta)}\)
Updated Wed, 18 Sep 2019 12:45 pm


Will the teachers in demo class are same in the real videos
Updated Mon, 16 Sep 2019 12:15 pm